PROBLEM 99
Hard

Student Performance Analysis

Programming Basics · JavaScript

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STATUS Not solved

TASK

Problem

#99

Given three scores 0..100. Print their average and status: EXCELLENT ≥90, GOOD ≥75, PASS ≥60, otherwise FAIL.

EXAMPLE

Example

Input
90 80 85
Output
85.0 GOOD

LIMITS

Constraints

0≤score≤100
📖
LEARN Theory for this problem
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### Student Performance Analysis

JavaScript arithmetic works with numeric values stored in variables. A clear solution reads the needed values, computes the formula with `+`, `-`, `*`, `/` or `**`, and prints only the final result.

💡
NEED HELP? Hints
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['Write the formula using named intermediate values if it contains more than one operation.', 'Consider a repeated key or value: the data structure must update exactly as required by the statement.']

ANSWER Solution
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const fs = require('fs');

const [a, b, c] = fs.readFileSync(0, 'utf8').trim().split(/\s+/).map(Number);
const average = (a + b + c) / 3;

let status;

if (average >= 90) {
    status = 'EXCELLENT';
} else if (average >= 75) {
    status = 'GOOD';
} else if (average >= 60) {
    status = 'PASS';
} else {
    status = 'FAIL';
}

const formattedAverage = Number.isInteger(average)
    ? average.toFixed(1)
    : String(average);

console.log(formattedAverage, status);