Two-Digit Number
Programming Basics · C++
TASK
Problem
An integer `n` is given. Print `YES` if its absolute value is a two-digit number; otherwise print `NO`.
EXAMPLE
Example
-12
YES
LIMITS
Constraints
All values are integers with magnitude at most 10^9.
LEARN
Theory for this problem
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Logical AND `&&`, OR `||`, and negation `!` combine boolean conditions. Parentheses make the intended grouping explicit.
Connection to “Two-Digit Number”: here, intermediate values are best kept in named variables so the formula stays readable and data types remain clear.
NEED HELP?
Hints
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['Translate the verbal condition into one boolean expression.', 'After solving “Two-Digit Number”, verify the algorithm on your own small example and on an allowed boundary case. Print only the required result with no extra text.']
ANSWER
Solution
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#include <iostream>
#include <cstdlib>
using namespace std;
int main() {
long long n;
cin >> n;
cout << ((10 <= llabs(n) && llabs(n) <= 99) ? "YES" : "NO") << '\n';
return 0;
}